$Light minimizes the time it takes to travel between two points. Let the top (white) region represent air and the bottom (blue) region represent Anna's vaginal emission, then the path light travels is represented by the ray connected A (the observer) down to B c d-x Figure 1: The path light is traveling as it passed from air into Anna's vaginal emission droplet. The total time for the light ray to travel is then T(x) (time from A to C) (time from C to B) Which, if we use the varibles as labeled in Figure (1), gives us T(x) ere v and v2 are the velocity of light in air and in Anna's vaginal droplet, respectively. Since light minimizes the time it takes to travel between these two points, we know that dT/dx 0, so dT Equation 3 looks complicated. But, if we take not of the relations in Figure (1), we find that they can be simplified into sin θ, sin θ 2 17 nair sin θ,-n anna sin θ 2 Where nair-c/V1 and nanna-c/½ Using Equation (5), and the knowledge that light form the sun is normal to the point of incidence striking Anna's vaginal emission droplets, we find that sin α nanna sin ain where α and β are the angles of the incidence and emittances (into the droplet) respectively. Drake et al (2013) have estimed that index of refraction of vaginal fluid simulant to be 1.40. We use this and estimate that nanna is 1.40 as well. Using this, setting nair to be 1, and Equation (6), we find that arccos 54.4 The result shown in Equation (6) is an angle of depression, given that the observer, Tanukichi and Kajo are above her [see Figure (2)] This cannot bo!!! Figure 2: Anna's rainbow as observed from above From this, we can back out how high this cliff must have been. Anna jumps at to-1095s and the rainbow becomes visible at t Principal tells us that 1100s so Δt 5s. The Momentum dt Which, for a uniform gravitation field with air resistance becomes, in the y direction dv 1 dt 2 Where p is the desnity of air and Cd is Anna's drag coefficient. (we omit the effects of air resistance orthogonal to the force of gravity because that has no effect on determining the height, only the distance traveled horizontally.) Air density p is constant, and Anna's shape doesn't change during the fall so her drag coefficient Cd is also constant. Solving Equation (8) for v gives 2mg tani 2mg (10) Where tanh x is the hyperbolic tangent function. Integrating Equation (9) with respect to t gives us In cosh-2 2mg pCdA where v- 2 Estimating that Anna's weight is 52.3kg, with a surface area of 1.6m2, using Equation (11) yields a distance fallen of 76m. This comports with the result of Equation (7) The average lethal fall height is 46m. Anna hasn't even finished falling at the time the vagina rainbow appears She's dead for sure$