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Jerach
Jerach

There's actually no single solution to this problem, it's kind of silly to be honest.

Let's say that roadhog is w, ana is x, lucio is y, and bastion is z. Then we have

(w+w) / w + w = 14

x + y + y = 6

y + z + x = 2

We see that the only value that w can be is 12, this is relatively straightforward. However when we get to the second two equations we don't have enough information to fix what, x, y, and z are. We have three unknowns but only 2 equations.

We know that x = 6 – 2y from the second equation and we can get that z = y – 4 from the last equation. Let's now look at the final equation:

w + z + z + x + y = ?

We get that this is the same as 12 + y – 4 + y – 4 + 6 – 2y + y = 10 + y.

The value of y can be anything though, any number we like and everything is still consistent. y = 5 works, y = -100000 works, anything I like will work here. The final equation can be equal to anything.

I'm not sure if this was the intention of the creator but it's at least more interesting than the standard form of this meme.

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